Let us say the original price of the camera is P. Assume we will have a discount of n%.
So the new value of camera `= (100-n)/100xxP`
Amount of discount
= Original value-Discounted value
According to our question amount of discount is $100.8 and the discount rate which is n is 28%.
`(nP)/100 =` Amount of discount
`28xxP/100 = 100.8`
` P = 360`
So the original price of the camera is $360.
You need to solve for p the following equation, yields:
`p - (28/100)*p = $100.80`
p represents the original price of camera
`p - 7/25*p = $100.80 => (18/25)*p = $100.80 => p = ($100.80*25)/18 => p = $140`
Hence, evaluating the original price of camera, yields `p = $140.`