Let us say the original price of the camera is P. Assume we will have a discount of n%.

So the new value of camera `= (100-n)/100xxP`

Amount of discount

= Original value-Discounted value

`= P-(100-n)/100xxP`

`= (100P-100P+nP)/100`

`= nP/100`

According to our question amount of discount is $100.8 and the discount rate which is n is 28%.

`(nP)/100 =` Amount of discount

`28xxP/100 = 100.8`

` P = 360`

*So the original price of the camera is $360.*

You need to solve for p the following equation, yields:

`p - (28/100)*p = $100.80`

p represents the original price of camera

`p - 7/25*p = $100.80 => (18/25)*p = $100.80 => p = ($100.80*25)/18 => p = $140`

**Hence, evaluating the original price of camera, yields `p = $140.` **

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