In Cambridge, England, a seconds pendulum is 0.9943 m long. What is the free-fall acceleration in Cambridge? 1. 9.81335 m/s^2 2. 9.81 m/s^2 3. None of these 4. 9.78366 m/s^2 5. 9.81441 m/s^2 6....

In Cambridge, England, a seconds pendulum is 0.9943 m long. What is the free-fall acceleration in Cambridge?

1. 9.81335 m/s^2

2. 9.81 m/s^2

3. None of these

4. 9.78366 m/s^2

5. 9.81441 m/s^2

6. 9.78473 m/s^2

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A seconds pendulum is one that takes one second to swing to an extreme position and return to the equilibrium position. This gives the time period of a seconds...

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senioreeto | Student

the answer is 9.81335 m/s2.

the formula for the time period of a simple pendulum is T=2 pi square root of (l/g).

using the given data,

l=0.9943m.

pi=3.1416.

T=2 sec.

solving the above equation for'g',we get the value of 'g' as 9.81335 m/s2 which is option (1).