# What constant acceleration is required to increase the speed of a car from 26 mi/h to 56 mi/h in 5 s? What constant acceleration is required to increase the speed of a car from 26 mi/h to 56 mi/h in 5 s? (Round your answer to two decimal places.) _____________ft/s^2

Start by stating your necessary unit conversions:

1 hr = 3600 s

1mi=5280 ft

The required formula to calculate acceleration is:

a = (v2 - v1) / t

where, a = acceleration, v2 =  final speed, v1 =  initial speed, and t = time

 v1 = 26 mi/h * 1/3600h/s * 5280 ft/mi

= 38.13 ft/s

v2 = 56  mi/h *1/3600 h/s *5280 ft/mi

= 82.13 ft/s

and finally, we know that t = 5s

We substitute our values and solve:

a = (82.13-38.13)/5

= 8.80 ft/s^2

:. The constant acceleration will be 8.80 ft/s^2.

Approved by eNotes Editorial Team

The value of the acceleration of the car over a duration of 5 seconds in terms of ft/s^2 to increase the speed from 26 miles/hr to 56 miles/hr has to be determined.

First convert the given speeds to ft/s.

26 miles/hr = 38.13 ft/s and 56 miles/hr = 82.13 ft/s.

The value of the acceleration is (82.12 - 38.13)/5 = 44/5 = 8.8 ft/s^2

An acceleration of 8.8 ft/s^2 is required to increase the speed from 26 mi/hr to 56 mi/hr in 5 s.

Approved by eNotes Editorial Team