Start by stating your necessary unit conversions:

`1 hr = 3600 s`

`1mi=5280 ft`

The required formula to calculate acceleration is:

`a = (v2 - v1) / t`

where, `a = `acceleration, `v2 = ` final speed, `v1 = ` initial speed, and `t = time`

` ``v1 = 26` mi/h `* 1/3600`h/s `* 5280` ft/mi

`= 38.13 ft/s`

`v2 = 56 ` mi/h `*1/3600` h/s `*5280` ft/mi

`= 82.13 ft/s`

and finally, we know that `t = 5s`

We substitute our values and solve:

`a = (82.13-38.13)/5`

`= 8.80` `ft/s^2`

**`:.` The constant acceleration will be `8.80 ft/s^2.` **

The value of the acceleration of the car over a duration of 5 seconds in terms of ft/s^2 to increase the speed from 26 miles/hr to 56 miles/hr has to be determined.

First convert the given speeds to ft/s.

26 miles/hr = 38.13 ft/s and 56 miles/hr = 82.13 ft/s.

The value of the acceleration is (82.12 - 38.13)/5 = 44/5 = 8.8 ft/s^2

**An acceleration of 8.8 ft/s^2 is required to increase the speed from 26 mi/hr to 56 mi/hr in 5 s.**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now