You need to evaluate the roots of equation f'(x) = 0 such that:

`(2x^2 -5x-12)/(3x^2 -7x+2) = 0 =gt 2x^2 -5x-12 = 0`

You should use quadratic formula such that:

`x_(1,2) =(5+-sqrt(25+96))/4`

`x_(1,2) =(5+-sqrt121)/4 =gt x_(1,2) =(5+-11)/4`

`x_1 = 4 ; x_2 = -6/4 = -3/2`

You should remember the law of signs of quadratic, hence, f'(x) has negative values between `(-3/2,4) ` and it has positive values in `(-oo,-3/2) ` and `(4,oo).`

**The function increases in `(-3/2,4) ` and it decreases in (-oo,-3/2) and `(4,oo).` **

**The function reaches its minimum at `x = -3/2` and its maximum at `x=4.` **

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