# calculate x in sin x-cos x/sin x+cos x=1, (0,360)

You need to solve for x in `(0,360^o)`  the equation `(sin x - cos x)/(sin x + cos x) = 1`  such that:

`(sin x - cos x)/(sin x + cos x)- 1 = 0`

You need to bring the terms to a common denominator such that:

`(sin x - cos...

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You need to solve for x in `(0,360^o)`  the equation `(sin x - cos x)/(sin x + cos x) = 1`  such that:

`(sin x - cos x)/(sin x + cos x)- 1 = 0`

You need to bring the terms to a common denominator such that:

`(sin x - cos x - sin x - cos x)/(sin x + cos x) = 0`

`- 2cos x/(sin x + cos x) = 0`

Since `sin x + cos x!=0` , you need to solve -`2cos x = 0`  such that:

`- 2cos x = 0 =gt cos x = 0 (-2!=0)`

`x = pi/2 and x = 3pi/2`

Hence, evaluating solutions to equation in `(0,360^o)`  yields `x = pi/2`  and `x = 3pi/2` .

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