Calculate the perimeter of triangle ABC. A(1,1) , B(0,3) , C(1,-1)

Expert Answers

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A(1, 1)  B(0, 3)    C(1, -1)

First we will calculate the measure of the sides:

AB = sqrt[(0-1)^2 + (3-1)^2]

       = sqrt( 1 + 4)

        = sqrt(5)

BC = sqrt[(1-0)^2 + (-1-3)^2]

       = sqrt(1+ 16)

        = sqrt(17)

AC = sqrt[(1-1)^2  + (-1-1)^2]

     = sqrt(0+ 4)

     = sqrt4 = 2

Then the perimeter is:

P = AB + BC + AC

   = sqrt5 + sqrt17 + 2

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