Calculate the number of moles of oxygen in 2.00L at 24 degrees Celsius and 750 torr.
First, we assume that the gas is ideal. Then, we use the ideal gas law:
`PV = nRT`
where P is the pressure, V the volume, n the number of moles, R the gas constant, and T absolute temperature.
This gives us:
`n = (PV)/(RT)`
Hence, substituting the given values:
`n = (PV)/(RT) = ((750/760)*2)/(0.08206*(24+273)) = 0.081 `
Answer is 0.081 moles of oxygen.
Note that temperature is in Kelvin, while pressure in atm (1 atm = 760 torr)