First, we need to write the chemical equation for this reaction:

`2 NaOH + H_2SO_4 -> Na_2SO_4 + 2 H_2O`

Looking from the balanced chemical equation, 2 moles of NaOH is required to neutralize 1 mole of H2SO4. Therefore:

`Mol es H_2SO_4 = (28.2)/(1000) L * 0.150`

`Mol es H_2SO_4 = 0.00423 mol es`

To get the moles of NaOH:

`Mol es of NaOH = (Mol es H_2SO_4)*2`

`Mol es of NaOH = (0.00423)*2 = 0.00846 mol es`

FInally, the molarity:

`Molarity = (Mol es NaOH)/(L of solution)`

`Molarity = (0.00846)/(0.035)`

Molarity = 0.242 M