Calculate logarithm base 30 of 8 if lg5=a and lg3=b

llltkl | Student

According to the logarithm change of base rule,


lg stands for log with base 10. So,



`=(3log2)/(log2+log3+log5)` ...........(i)

Again, log2=log(10/5)=log10-log5 =1-a [ since log5=a....(given)]

Now, putting the values of log2, log3 and log5 in (i) we get:

`log_(30)8` =`(3*(1-a))/(1-a+b+a)`


Hence, the required answer is `(3-3a)/(1+b)`

Access hundreds of thousands of answers with a free trial.

Start Free Trial
Ask a Question