Calculate the kinetic energy of a proton which moves into a field of induction B=167mT, on a circle with radius r=50cm.

1 Answer

giorgiana1976's profile pic

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

Lorentz force is acting on electron, so lex secunda is giving the followings:

module (q*vxB)=e*v*B=m*ac=m*v^2/r, so v=(r/m)*e*B