Calculate Kc For The Following Equilibrium 2so2 O2
Calculate Kc for the following equilibria:
2SO2(g) +O2(g) ====> 2SO3(g)
Kp= 2.5x10^10 at 500K
1 Answer
jeew-m | College Teacher | (Level 1) Educator Emeritus
`2SO_(2(g))+O_(2(g)) harr 2SO_(3(g))`
The relationship of the `K_c` and `K_p` for the above equilibrium is given by;
`k_p = k_c(RT)^(Deltan)`
`Deltan =` (total gas moles of products)-(total gas moles of reactants)
`Deltan = (2-(2+1))`
`R = 8.314 J mol^(-1) K^(-1)`
`T = 500K`
`K_c = (K_p)/(RT)^(Deltan)`
`K_c = (2.5xx10^10)/(500xx8.314)^((2-(2+1)))`
`K_c = 1.039xx10^14M^(-1)`
So the answer is `K_c = 1.039xx10^14M^(-1)`.
Note:
According to the value of `K_p` we can assume that it has units of `pa^(-1)`