Calculate how many seconds an outfielder has to position himself for the catch if he intends to catch the ball 6 feet above the ground
Time(sec) .75 1.5 2 2.75 3.25 4.75
Height(ft) 77 133 160 187 194 169
1 Answer | Add Yours
Using the linear regression from the calculator the quadratic function for this set of data is:
f(t) = -15.94t^2 + 110.20 t + 4.87
We find the time when the ball is 6 feet above the ground, thus we have to set f(t) = 6.
6 = -15.94t^2 + 110.20 t + 4.87
(0 = -15.94t^2 + 110.20 t -1.13) -1
0 = 15.94t^2 - 110.20 t + 1.13
a b c
Then we can use the quadratic formula to solve the answer.
`t = (-b +- sqrt(b^2-4ac))/(2a) `
by substituting the values of a, b and c, we can get the value of t = 6.903 and 0.0102 seconds. Quadratic equations have two answers and you have to choose the later one.
You will have 6.903 seconds to get into the position.
We’ve answered 319,667 questions. We can answer yours, too.Ask a question