Calculate the frequency if vector H = xsin(10^7pi t-0.2z)+ycos(10^7pi t-0.2z-5/2pi)?
In the given expression for vector H, the coefficient in front of time t
is the angular frequency: `omega=10^7pi`
Angular frequency `omega` and frequency f are related by the expression
`f = omega/(2pi)`
So from here the frequency is
`f = (10^7pi)/(2pi) = 5*10^6` Hz