The gravitational force between two masses act along the line that connects the two masses and it is an attractive force. The value of this force is directly proportional with the values of the two masses `m_1` and `m_2` and inversely proportional with the square of the distance between the...

## See

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

The gravitational force between two masses act along the line that connects the two masses and it is an attractive force. The value of this force is directly proportional with the values of the two masses `m_1` and `m_2` and inversely proportional with the square of the distance between the two objects.

`F = G*(m_1*m_2)/R^2`

Here above G is the gravitational constant.

With the values given in the problem text one has

`F = 6.67*10^-11*(70*2000)/1^2 =9.338*10^-6 N`

**Answer: The interaction force between the two masses given in the problem is 9.338*10^-6 N**