At the extreme values of a function f(x), the first derivative f'(x) = 0

f(x) = 3x^2 - 4x + 5

f'(x) = 6x - 4

6x - 4 = 0

=> x = 4/6

=> x = 2/3

The extreme value of the function is f(2/3) = 3*4/9 - 4*2/3 + 5

=> 4/3 -...

(The entire section contains 2 answers and 107 words.)

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