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Determine the derivative of `-7 / (2x^2-8x+16)`

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The derivative of f(x) = `-7/(2x^2-8x+16)` has to be determined. Use the quotient rule.

f'(x) = `((-7)'*(2x^2-8x+16) - (-7)*(2x^2-8x+16)')/(2x^2-8x+16)^2`

=> `(7*(4x - 8))/(2x^2-8x+16)^2`

=> `(7*(x - 2))/(x^2-4x+8)^2`

=> `(7x - 14)/(x^2-4x+8)^2`

The derivative of `-7/(2x^2-8x+16)` is `(7x - 14)/(x^2-4x+8)^2`

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The derivative of f(x) = `-7/(2x^2-8x+16)` has to be determined. Use the quotient rule.

f'(x) = `((-7)'*(2x^2-8x+16) - (-7)*(2x^2-8x+16)')/(2x^2-8x+16)^2`

=> `(7*(4x - 8))/(2x^2-8x+16)^2`

=> `(7*(x - 2))/(x^2-4x+8)^2`

=> `(7x - 14)/(x^2-4x+8)^2`

The derivative of `-7/(2x^2-8x+16)` is `(7x - 14)/(x^2-4x+8)^2`

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