Calculate the concentration of the Cl- in the water. AgNO3 + Cl- <--> AgCl + NO3 Net: AgCl <--> Ag+ + Cl- The Cl- is diluted in 25 mL water. [AgNO3] = 0.1 M The volume of AgNO3 used is 0.6 mL. I know it looks easy but the "25 mL water" part is bothering me. Help please?

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We are looking for the concentration of chlorine ion in the reaction.  We know that the volume of the chlorine solution is 25 mL, so if we can calculate the moles of chloride we can figure out the concentration of the chloride ion.  We know that silver nitrate is present...

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We are looking for the concentration of chlorine ion in the reaction.  We know that the volume of the chlorine solution is 25 mL, so if we can calculate the moles of chloride we can figure out the concentration of the chloride ion.  We know that silver nitrate is present in 0.1 M and it took 0.6 mL to fully react with the chloride ion, so 0.1 mole/L*(0.0006 L) = 0.00006 moles.  Since the ratio of silver to chloride is 1:1, then that also means that there are 0.00006 moles of chloride.  We divide the moles by 0.025 L to give the chloride concentration:

0.00006 moles/0.025 L = 0.0024 M Cl-

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