Calculate the concentration of chloride ions in the solution, in mol L^-1.
Each 200 mL of an electrolyte solution designed for treating dehydration contains 0.47 g of sodium chloride (NaCl), 0.30 g of potassium chloride (KCl) and 3.56g of glucose (C6H12O6).
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The electrolyte solution contains sodium chloride NaCl, potassium chloride KCl and glucose. From one atom each of NaCl and KCl, one chloride ion is supplied to the electrolyte solution.
The molar mass of sodium chloride is 58.44.
0.47 g of sodium chloride is equivalent to 0.47/58.44 = 8.04*10^-3 moles
The molar mass of potassium chloride is 74.55
0.3 g of potassium chloride is equivalent to 0.3/74.55 = 4.02*10^-3 moles.
The total number of moles of Cl- ions supplied by NaCl and KCl is 12.06*10^-3.
The volume of the solution is 200 mL. This gives the concentration of the chloride ions in terms of mole/liter as 12.06*10^-3/0.2 = 60.3 mole/liter.
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