Calculate the common population variance for ALL the following data (to at least three places of decimals) Calculate the common population variance for the following data (to at least three places of decimals)   The mean number of flowers per plant for Sample 1 = 6.44 and Sample 2 = 7.20 The estimated population standard deviation of number of flowers per plant Sample 1 = 1.51 and Sample 2 = 1.80   And Sample size for Sample 1 = 9 and Sample 2 = 20 Calculate S^2/c  (the common population variance) for these data (to at least three places of decimals). S^2/c =    

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Since the problem provides the values of mean and deviation for each of the given samples, you should evaluate common population variance such that:

`sigma^2 = ((x - bar x)^2)/(n-1)`

You need to substitute 6.44 for the mean and 1.51 for the deviation in the formula of variance such that:

`sigma_1^2...

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Since the problem provides the values of mean and deviation for each of the given samples, you should evaluate common population variance such that:

`sigma^2 = ((x - bar x)^2)/(n-1)`

You need to substitute 6.44 for the mean and 1.51 for the deviation in the formula of variance such that:

`sigma_1^2 = ((6.44 - 1.51)^2)/(9-1)`

`sigma_1^2 = 3.038`

Hence, evaluating the variance of population for the sample 1 yields `sigma_1^2 = 3.038.`

You need to substitute 7.20 for the mean and 1.80 for the deviation in the formula of variance such that:

`sigma_2^2 = ((7.20-1.80)^2)/(20-1)`

`sigma_2^2 = 1.534`

Hence, evaluating the variance pf population for sample 2 yields `sigma_2^2 = 1.534.`

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