You need to use the work equation to find the work done such that:

`W = F*d*` cos(angle made by direction of force to x axis)

The problem provides the force F = 30N, the displacement d = 50 m and the angle between force and displacement `alpha = 30^o` , hence you may substitute these values in work equation such that:

`W = 30*50*cos30^o`

`W = 1500*sqrt3/2`

`W~~ 1299J`

**Hence, evaluating the amount of work done under given conditions yields `W ~~ 1299 J` .**

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