Calculate a10 if a4 = 19, a1 = 10, a1 and a4 being the terms of A. P.

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hala718's profile pic

hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted on

a1, a2, ....a10     are terms in an arthimatical progression

10, a2, a3, 19, ..., a10

We know that:

a1= 10

a2= 10+r

a3= 10 + 2r

a4= 10 + 3r = 19

==> 3r = 9

==> r= 3

Now let us calculate a10:

a10 = a1+ 9r

       = 10 + 9*3

       = 10+27

        = 37

==> a10 = 37

Top Answer

giorgiana1976's profile pic

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

To calculate a10, we'll write the formula of the general term of an arithmetical progression:

an = a1 + (n-1)*r

a10 = a1 + (10-1)*r

a10 = 10 + 9r

We don't know yet the ratio r. But we know a4 = 19

a4 = a1 + 3r

19 = 10 + 3r

We'll subtract 10 both sides:

3r = 9

We'll divide by 3:

r = 3

Now, we can calculate a10.

a10 = 10 + 9r

a10 = 10 + 9*3

a10 = 10 + 27

a10 = 37

neela's profile pic

neela | High School Teacher | (Level 3) Valedictorian

Posted on

a4 = 19, a1 = 10 to find a10 of the AP.

Solution:

For an Arithmetic progression, the rth term ar = a1+(r-1)d, where d  is the common difference. So,

a4  - a1 = a1+3d-a1 = 3d

Here a4 -a1 = 19- 10 = 9

3d =9

d =3.

S0 a10 = a1+(10-1)d = 10 +(10-1)*3 = 37

krishna-agrawala's profile pic

krishna-agrawala | College Teacher | (Level 3) Valedictorian

Posted on

I believe the initial A.P. used in the question for arithmetic progression, and the terms a1, a4 and a10 refer to the first, fourth and tenth term of the progression.

In an arithmetic progression the difference (d) between any two consecutive terms is same.

Thus the different terms of the progression can be represented as:

a1= a1

a2 = a1 +d

a3 = a1 + 2d

a4 = a1 + 3d

...

an = a1 + (n -1)*d

It is given:

a1 = 10, and a4 = 19

Therefore:

a4 = 19 = a1 + 3d = 10 + 3d

3d = 19 - 10 = 9

Therefore:

d = 9/3 = 3

Therefore:

a10 = a1 + (10 - 1)d

= 10 + 9*3

= 10 + 27 = 37

Answer:

a10 = 37

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