Calculate 1+2x+3x^2+4x^3+---+99x^100.

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I assume that the last term of requested summation is `100x^99` , since it needs to follow the pattern of previous terms.

You need to evaluate the given summation such that:

`1+2x+3x^2+4x^3+...+100x^99 = sum_(k=1)^100 k*x^(k-1)`

You need to notice that differentiating the function `y = x^k` with respect to x,...

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I assume that the last term of requested summation is `100x^99` , since it needs to follow the pattern of previous terms.

You need to evaluate the given summation such that:

`1+2x+3x^2+4x^3+...+100x^99 = sum_(k=1)^100 k*x^(k-1)`

You need to notice that differentiating the function `y = x^k` with respect to x, yields the product `(dy)/(dx) = k*x^(k-1)` .

`1+2x+3x^2+4x^3+...+100x^99 = (d (sum_(k=1)^100 x^k))/(dx) `

Evaluating the summation `sum_(k=1)^100 x^k` yields:

`sum_(k=1)^100 x^k = (1 - x^101)/(1 - x)`

`1+2x+3x^2+4x^3+---+100x^99 = (d((1 - x^101)/(1 - x)))/(dx)`

Hence, you need to use the quotient rule to evaluate the derivative `(d((1 - x^101)/(1 - x)))/(dx)` , such that:

`(d((1 - x^101)/(1 - x)))/(dx) = ((1 - x^101)'(1 - x) - (1 - x^101)(1 - x))/((1 - x)^2)`

`(d((1 - x^101)/(1 - x)))/(dx) = (-101x^100(1 - x) + 1 - x^101)/((1 - x)^2)`

`(d((1 - x^101)/(1 - x)))/(dx) = (-101x^100 + 101x^101 + 1 - x^101)/((1 - x)^2)`

`(d((1 - x^101)/(1 - x)))/(dx) = (100x^101 - 101x^100 + 1)/((1 - x)^2)`

Hence, evaluating the summation `1+2x+3x^2+4x^3+...+100x^99` , using derivatives and summation of terms of geometric series, yields `1+2x+3x^2+4x^3+...+100x^99 = (100x^101 - 101x^100 + 1)/((1 - x)^2).`

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