The displacement of the particle moving in a straight line as a function of time is s = t^2 - 8t + 19.

The average velocity over a time interval [a, b] is:

(b^2 - 8b + 19 - a^2 + 8a - 19)/(b - a)

=> (b^2 - a^2 - 8b + 8a)/(b - a)

=> ((b-a)(b +a) - 8(b - a))/(b - a)

=> a + b - 8

The instantaneous velocity at time t is 2t - 8. At t = 4 it is 0 m/s.

**The average velocity over an interval [a, b] is a + b - 8 m/s and the instantaneous velocity at t = 4 is 0 m/s.**

## See eNotes Ad-Free

Start your **48-hour free trial** to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Already a member? Log in here.