Given that :
`sinx = 8/17`
We know that:
`sin^2 x + cos^2 x = 1 `
`==> cosx = sqrt(1-sin^2 x)= sqrt(1- 8^2/17^2) = 15/17`
==> `cosx = 15/17`
Now we will find the required identity.
==> We know that `sin2x = 2sinx cosx `
`==> sin2x = 2*8/17 * 15/17 = 240/17`
`==> cos2x = cos^2 x - sin^2 x = (15/17)^2 - (8/17)^2 = 161/289`
`==gt tan2x = (sin2x)/(cos2x)= (240/17)/(161/289)= (240*17)/(161) ~~ 25.34`
See eNotes Ad-Free
Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.
Already a member? Log in here.