If f(x) = ex − 3, 0 ≤ x ≤ 2,find the Riemann sum with n = 4 correct to six decimal places, taking the sample points to be midpoints.If f(x) = ex − 3, 0 ≤ x ≤ 2,find the Riemann sum with...

If f(x) = ex − 3, 0 ≤ x ≤ 2,find the Riemann sum with n = 4 correct to six decimal places, taking the sample points to be midpoints.

If f(x) = ex − 3, 0 ≤ x ≤ 2,find the Riemann sum with n = 4 correct to six decimal places, taking the sample points to be midpoints.

M4=____________

Asked on by esma2

1 Answer | Add Yours

sciencesolve's profile pic

sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted on

You need to find the interval width `Delta x`  using the following formula such that:

`Delta x = (b-a)/n`

`Delta x = (2-0)/4 =gt Delta x = 2/4 =gt Delta x = 1/2`  = 0.5

You need to evaluate the midpoints of intervals [0,0.5] , [0.5,1] , [1,1.5] , [1.5, 2] such that:

`x_1 = (0+0.5)/2 = 0.25`

`x_2 = (0.5+1)/2 = 0.75`

`x_3 = (1+1.5)/2 = 1.25`

`x_4 = (1.5+2)/2 = 1.75`

You need to use the formula of Riemann's sum such that:

`R_4 =`  `sum_(i=1)^4``f(x_i)*Delta x`

`R_4 = (1/2)*(f(x_1) + f(x_2) + f(x_3) + f(x_4))`

`R_4 = (1/2)*(f(0.25) + f(0.75) + f(1.25) + f(1.75))`

`R_4 = (1/2)*(e^0.25 - 3 + e^0.75 - 3 + e^1.25 - 3 + e^1.75 - 3)` `R_4 = (1/2)*(2.2795 + 2.1063 + 3.4610 + 5.6870 - 12)` =>`R_4 = 0.7669`

Hence, evaluating the Riemann's sum under given conditions yields `R_4 = 0.7669.`

We’ve answered 318,982 questions. We can answer yours, too.

Ask a question