Find the value of `int_(-1)^2 4/(x^3) dx`

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The value of `int_(-1)^2 4/x^3 dx` has to be determined.

`int 4/x^3 dx = 4*x^-2/-2 = -2/x^2`

Between the limits -1 and 2 the value is:

`-2(1/4 - 1/1) `

=> `-2(-3/4)`

=> ` 3/2`

The value of `int_(-1)^2 4/x^3 dx = 3/2`

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