Use the Newton iteration formula:

`x_2=x_1-f(x_1)/f'(x_1)`

In our case, `f(x_1)=-1-1+7=5`

`f'(x)=3x^2+1`

`f'(x_1)=3(-1)^2+1=4`

`x_2=-1-(5)/4=-9/4`

Answer: `x_2=-9/4`

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