cake wghs 550g & has 3 ing. flour sugar & raisins Theres twice as much flour as sugar & one & a half times as much sugar as raisins
this problem is related to ratios and have to find how much flour is there?
Let raisins weigh x gram.
Then sugar should weigh 1.5 times raisin = 1.5x
Flour weight = 2times sugar = 2*1.5 = 3x.
So the total contents of cake = x+1.5x+3x = 5.5x.
Therefore 5.5x = 550 gram
x= 550/5.5 = 100gram
Therefore the content of flour = 3x = 3*100 = 300gram.
The total weight of the cake is 550g. Let the weight of raisins be R.
As the cake has one and a half as much sugar as raisins, the weight of sugar is (3/2)*R
Now as the cake has twice as much flour as sugar, and the weight of sugar has already been expressed as (3/2)*R, the weight of flour is 2*(3/2)*R = 3*R
So the sum of all the three is 550
=> R + (3/2)*R + 3*R = 550
=> R (1 + 3/2 + 3) = 550
=> R ( 11/2 ) = 550
=> R = 550/ (11/2)
=> R = 1100/11 = 100 g
So the weight of flour in the cake is 3*100 = 300g