The mass of the bullet is 10 g. The mass that is hung is of 5 kg. When the bullet strikes the mass its height increases by 10 cm.

The potential energy of the mass changes by m*g*h = 5*(10/100)*9.8

This potential energy is imparted by the bullet that strikes...

## Unlock

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

The mass of the bullet is 10 g. The mass that is hung is of 5 kg. When the bullet strikes the mass its height increases by 10 cm.

The potential energy of the mass changes by m*g*h = 5*(10/100)*9.8

This potential energy is imparted by the bullet that strikes the hung mass.

It does not make a difference if the bullet is embedded in the 5-kg mass or has passed through it because its mass of 10 g is negligible compared to that of the mass that is hung.

The kinetic energy in a body of mass 10 g travelling at a velocity of V m/s is (1/2)*(10/1000)*V^2

This is equal to the change in the kinetic energy

=> (1/2)*(10/1000)*V^2 = 5*(10/100)*9.8

=> V^2 = (100)*9.8

=> V^2 = 98

=> V = sqrt 98

=> V = 7 * sqrt 2 m/s

**The velocity of the bullet is 7* sqrt 2 m/s**