a bullet enters an apple at a velocity of 200m/s. it emerges from the other side of the apple at a velocity of 180m/s just 0.00005 s later. find the deceleration of the bullet on passing through the apple
To solve, apply the formula of acceleration which is:
a - acceleration
`v_f` - final velocity
`v_i ` - initial velocity
t - time
So, plug-in `v_i` =200 m/s, `v_f` =180 m/s and t=0.00005 s.
Since the value of a is negative, it indicates that the bullet decelerates.
Hence, the deceleration of the bullet when it passes through the apple is `400000 m/s^2` .