a bullet enters an apple at a velocity of 200m/s. it emerges from the other side of the apple at a velocity of 180m/s just 0.00005 s later. find the deceleration of the bullet on passing through...

a bullet enters an apple at a velocity of 200m/s. it emerges from the other side of the apple at a velocity of 180m/s just 0.00005 s later. find the deceleration of the bullet on passing through the apple

Expert Answers
lemjay eNotes educator| Certified Educator

To solve, apply the formula of acceleration which is:

`a=(v_f-v_i)/t`

where

a  -  acceleration

`v_f`  -  final velocity

`v_i `  -  initial velocity

t  -  time

So, plug-in `v_i` =200 m/s, `v_f` =180 m/s and t=0.00005 s.

`a=(180-200)/0.00005`

`a=(-20)/0.00005`

`a=-400000`

Since the value of a is negative, it indicates that the bullet decelerates.

Hence, the deceleration of the bullet when it passes through the apple is  `400000 m/s^2` .

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