A box of mass 20 kg is at rest on a rough horizontal floor. The coefficient of friction between the box and the floor is 0·3. The box is subjected to a horizontal force of TN.
Given that T = 65, find the frictional force and magnitude of the acceleration of the box
1 Answer | Add Yours
Refer to the attached image for the given situation.
`rArr F_(norm)=F_(grav)=m*g=20*9.81=196.2 N`
Again, along the x-direction,
F_(fric)=coefficient of friction*F_(norm)
Acceleration, a = F_(net)/m
Therefore, the frictional force on the surface is 58.86 N and magnitude of the acceleration of the box is 0.307 m/s^2.
We’ve answered 318,916 questions. We can answer yours, too.Ask a question