A box has chocolates which are divided among A, B and C in the ratio 4: 3: 1. If A gets 32 chocolates more than C, how many does B get?
Let the number of chocolates in the box be N. When they are distributed among A, B and C in the ratio 4: 3: 1, the number of chocolates that A gets is 4N/ 8 and C gets N/8 chocolates.
As A gets 32 more chocolates than C
4*N/8 - N/8 = 32
=> 3N/8 = 32
=> N = 32*8/3
B gets 3/8 of the total number of chocolates. This is equal to (32*8/3)*(3/8)
The number of chocolates that B gets is 32, though it should be noticed that the total number of chocolates in the box does not come to a whole number.
B gets 32 chocolates.