Before any cards are taken there is a 2:4; that is, 1:2 chance of picking either 0 or 1.

As one card is taken - a 0- the probability changes : only one card is a 0 and two cards are a 1 so the ratio changes to a 1:3 chance as the first card was retained.

Similarly for the other card. You can deduce the answer in the same manner: There are 3 cards left and only one of them is a 1. Therefore the chance is also 1:3

**1:3 **is the probability of taking a 0 from the pack on the second draw in the event a 0 was selected in the first draw and not returned and similarly for the number 1 under the same conditions - removing a 1 in the first draw.

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