# A board 39 feet long is cut into 2 parts such that the length of the larger piece is 3 feet more than twice the length of the smaller piece. Find the length of each part.Show the GIVEN, REQUIRED,...

A board 39 feet long is cut into 2 parts such that the length of the larger piece is 3 feet more than twice the length of the smaller piece. Find the length of each part.

Show the GIVEN, REQUIRED, SOLUTION, AND ANSWER to the word problem.

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Given:

Length of the board = 39 ft

Length of the larger piece is 3 more than twice the smaller piece.

Required:

Length of both pieces.

Solution:

Let the length of the smaller piece is L.

Then the length of the larger piece is 2L+3

But we know that the length of both pieces is 39 ft.

==> 39= L + (2L+3)

==> 39 = L +2L + 3

==> 39 = 3L + 3

Now we will solve for L.

==> 3L + 3 = 39

We will subtract 3 from both sides:

==> 3L = 39-3

==> 3L= 36

Now we will divide by 3.

==> L = 36/3 = 12

Then, the length of the small piece is L= 12 and the length of the larger piece is 2L+3 = 2*12+3= 27

To check we will add both pieces we get 12 + 27= 39

**Then, the length of the smaller piece is 12 ft, and the length of the larger piece is 27 ft.**