A block of mass 3.73 kg is pushed 2.68m along a frictionless horizontal table by a constant 16 N force directed 24 degrees below the horizontal. What is the work done by: the applied force, the normal force exerted by the table, the force of gravity and the work done by the net force on theblock.

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The work done by a force on an object when it is displaced is given by W = F*D*cos x, where the W is the work done, F is the force applied, D is the displacement and x is the angle between the force applied and the resultant displacement.

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The work done by a force on an object when it is displaced is given by W = F*D*cos x, where the W is the work done, F is the force applied, D is the displacement and x is the angle between the force applied and the resultant displacement.

Here a force of 16 N is applied on the block and it has a direction 24 degrees below the horizontal. The resultant displacement is 2.68 m.

The work done by the force is 16*2.68*cos 24 = 18.19 J

The work done by the normal force is zero as the angle between the direction of the displacement and the direction of the normal force is 90 degrees. Similarly the gravitational force of attraction also makes an angle of 90 degrees with the direction of displacement.

The work done by the net force on the block is 18.19 J

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