A block explodes into three pieces of equal mass. Piece A has speed `v` after the explosion, and pieces B and C have speed `2v` . What is the angle between the direction of the piece A and the piece B?

Expert Answers

An illustration of the letter 'A' in a speech bubbles

Here we need the conservation of momentum law. I suppose that before the explosion the block was in rest thus its momentum was zero. The law states that after the explosion the total momentum of the pieces is also zero (if we ignore the mass and speed of explosives).

Momentum...

Unlock
This Answer Now

Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Start your 48-Hour Free Trial

Here we need the conservation of momentum law. I suppose that before the explosion the block was in rest thus its momentum was zero. The law states that after the explosion the total momentum of the pieces is also zero (if we ignore the mass and speed of explosives).

Momentum is a vector quantity and the total momentum is a vector sum. Denote the mass of each piece as m. Then

`m vec V_1+m vec V_2+m vec V_3=0,`  or  `vec V_1+vec V_2+vec V_3=0`

(look at the picture attached).

 

Projections on the `x` and `y` axes give us

`-v+2v cos alpha + 2v cos beta =0,`  or  `2(cos alpha + cos beta)=1,`  and

`2v sin alpha = 2v sin beta,`  so  `alpha = beta.`

 

Thus from the first equation we have

`4cos alpha=1,` or  `alpha=arccos(1/4) approx 75.5^@.`

The angle in question is  `180^@-alpha approx 104.5^@.`

 

Images:
This image has been Flagged as inappropriate Click to unflag
Image (1 of 1)
Approved by eNotes Editorial Team