The bird flying horizontally with a velocity 12 m/s drops a fish above its nest from a height 250 m.
As the fish is dropped, its initial velocity is 0. The time (t) taken by the fish to reach the ground is given by `250 = (1/2)*9.8*t^2`
=> `t = sqrt(500/9.8)`
In this duration of time, the horizontal distance traveled by the fish is `12*sqrt(500/9.8) = 600/7 ~~ 85.71` m
The fish dropped by the bird lands at a spot that has a horizontal distance of 95.71 m from the bird's nest.