The height at which the bird flies (y) is related to the distance from its nest by y = 3x^3 + 2x^2 - 10x + 5.

The graph of the relation is:

The distance of the bird from its nest is a positive number (as this is the magnitude of a vector). From the graph it is evident that there is no limit to how large y can be for positive values of x.

To determine the lowest value of y, calculus can be used to determine y' and y''. Solve y' = 0 for x

y' = 9x^2 + 4x - 10

y' = 0

=> 9x^2 + 4x - 10 = 0

The positive root of the equation is `(sqrt 94 - 2)/9` . At this point the value of y is negative and equal to -0.2128.

But the height of a bird (using logic) cannot be negative, it cannot fly below the surface.

**In case the height can take on negative values, the minimum height of the bird is -0.2128**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now