A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4m. Determine the acceleration of the bike.

aruv | Student

Let acceration of the bike  is a m/sec^2.

Bike started from rest so its initial speed  will zero i.e.


It reaches  at a speed of 7.10 m/s  i.e final speed  v= 7.10 m/s

In reaching speed 7.10 m/s ,it covered distance 35.4 m.

Apply equation of motion which relates u ,v ,a and s


`(7.10)^2=(0)^2+2 a (35.4)`



So acceleration of the bike which started from rest , reaches at speed of 7.10 m/s by travelling distance 35.4 m will be 0.712 m/sec^2.

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