# A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4m. Determine the acceleration of the bike.

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Let acceration of the bike is a m/sec^2.

Bike started from rest so its initial speed will zero i.e.

u=0

It reaches at a speed of 7.10 m/s i.e final speed v= 7.10 m/s

In reaching speed 7.10 m/s ,it covered distance 35.4 m.

Apply equation of motion which relates u ,v ,a and s

`v^2=u^2+2as`

`(7.10)^2=(0)^2+2 a (35.4)`

`50.41=70.8a`

`a=0.712ms^(-2)`

So acceleration of the bike which started from rest , reaches at speed of 7.10 m/s by travelling distance 35.4 m will be 0.712 m/sec^2.