A balloon rubbed against denim gains a charge of -15.0 micro coulombs. What is the electric force between the balloon and the denim when the 2 are separated by a distance of 2.0 cm?

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justaguide | College Teacher | (Level 2) Distinguished Educator

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The force of attraction between two oppositely charged bodies with charges q1 and q2 is equal to F = C*q1*q2/r^2, where r is the distance between the bodies and C = 8.987*10^9 N*m^2/C^2

When the balloon is rubbed against the denim there is an movement of electrons from the denim to balloon that charges the balloon to -15 micro coulombs. In turn, the denim has a positive charge of +15 micro coulombs.

At a distance of 2 cm or 2*10^-2 m, the force of attraction between the two is: 8.987*10^9*15*10^-6*15*10^-6/(2*10^-2)^2

=> 8.987*10^9*225*15*10^-12/(4*10^-4)

=> 8.987*10^9*225*10^-12/(4*10^-4)

=> 5055.1 N

The force between the denim and the balloon is 5055.1 N