Start with finding the time it takes it to reach the highest point at which the velocity = 0 and it will start reversing its path due to gravity.

This can be found from the equation v = u - gt (note gravity works against the ball hence the -ve sign). v is final velocity which is 0, g is acceleration of gravity 9.81 m/s^2 , u is initital velocity of 24 m/s and t is the time it takes to attain a zero velocity

Therefore,

0 = 24 - 9.81 *t

solving, t = 24/9.81 = 2.45 sec

(a) The vertical distance it travels is how high it will go, which is represented by

s = ut - 1/2 *g*t^2 (note the -ve sign for g here as well)

= 24 * 2.45 - 1/2* 9.81 * 2.45^2 = 29.35m

(b) Time t = 2.45 sec al already calculated

(c) This can be obtained from same equation s = ut + 1/2 *g*t^2, except in this case g is +ve as gravity works for the fall and initial...

(The entire section contains 2 answers and 434 words.)

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