1 Answer | Add Yours
To solve for t, use the formula:
`s=v_it + 1/2at^2`
where `s` - displacement `v_i` - initial velocity
`t` - time `a` - accelaration
Note that displacement refers to the change in height. So value of s is:
Also, acceleration is equal to gravity since the ball exhibits the principle of freely falling bodies. Its sign is negative because the direction of the intial velocity is upward. So, `a=-9.81 m/s^2` .
Then, substitute `s=-3.82` , `v_i=1.86` and `a=-9.82` .
`-3.82=1.86t + 1/2(-9.82)t^2`
Express the equation in quadratic form `ax^2+bx+c=0` .
Apply the quadratic formula to solve for t.
`t_1=1.09` and `t_2= -0.71`
Since t represents time, take only the positve value.
Hence, the time it takes for the ball to reach the ground is 1.09 seconds.
We’ve answered 318,915 questions. We can answer yours, too.Ask a question