To solve, apply the third formula.
`v_(fy)^2 = v_(iy)^2+2gd_y`
Take note that when the ball reaches the maximum height, its velocity is zero. So plugging in the values
`v_(iy)=9.8` m/s
`v_(fy) = 0`
`g=-9.8` m/s^2
the formula becomes
`0^2= 9.8^2 + 2(-9.8)d_y`
`0=96.04 - 19.6d_y`
`19.6d_y = 96.04`
`d_y=96.04/19.6`
`d_y=4.9`
Therefore, the maximum height of the ball is 4.9 meters.
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