If a ball is thrown into the air with a velocity of 40 ft/s, its height in feet seconds later is given by y = 40t -16t^2.Find the average velocity for the time period beginning when t = 2 and lasting ,0.5 second ,0.1 second, 0.05 second and 0.01 second. What is the instantaneous velocity when t = 2.

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A ball is thrown into the air with an initial velocity of 40 ft/s vertically upwards. t seconds after it has been thrown up, the height of the ball is given by the function `f(t) = 40t - 16t^2` .

The average velocity of the ball for a time period between `t_0` and `t_1` is given by:

v = `(f(t_1) - f(t_0))/(t_1 - t_0)`


(The entire section contains 150 words.)

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