A ball rolls across a floor with an acceleration of 0.100 m/s^2 in a direction opposite to its velocity. The ball has a velocity of 4.00 m/s after rolling a distance 6.00 m across the floor.

Let the initial velocity of the ball be X.

2*(-0.1)*6 = 4^2 - X^2

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A ball rolls across a floor with an acceleration of 0.100 m/s^2 in a direction opposite to its velocity. The ball has a velocity of 4.00 m/s after rolling a distance 6.00 m across the floor.

Let the initial velocity of the ball be X.

2*(-0.1)*6 = 4^2 - X^2

=> X^2 = 17.2

=> X `~~` 4.147

**The initial speed of the ball was approximately 4.147 m/s**