# A ball rolling at constant velocity on a table 0.6 m high rolls off the edge and hits the ground 0.352 m from the edge of the table. How fast was the ball rolling?

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### 1 Answer

The ball is rolling at a constant velocity on a table at a height of 0.6 m. It rolls off the edge of the table top and travels downward landing at a point 0.352 m from the edge of the table. The constant speed at which the ball was rolling has to be determined.

Let the speed of the ball be S. As it lands at a point 0.352 m from the edge of the table the time spent traveling in the horizontal direction is (0.352/S). The ball also falls vertically downwards due to the acceleration of gravity. The distance it falls is 0.6 m. The time taken by it to do so is t where 0.6 = (1/2)*9.8*t^2

=> t^2 = 6/49

substituting t = 0.352/S gives (0.352/S)^2 = 6/49

=> 0.352/S = sqrt 6/7

=> S = 7*0.352/sqrt 6

=> S = 1.00 m/s

The constant velocity at which the ball was moving on the table is 1.00 m/s

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