You need to remember the formula of momentum such that:

`p = m*v`

You should use the kinematic equation that helps you to find the velocity such that:

`v^2 = v_0^2 + 2a*x`

Since the initial velocity is zero,the acceleration is g and h represents the height the ball is dropped, you need to substitute these values in the kinematic equation above such that:

`v^2 = 2g*h =gt v = sqrt(2gh)`

Substituting `sqrt(2gh)` for v in equation of momentum yields:

`p = m*sqrt(2gh)`

`p = 0.1*sqrt(2*9.8*12) =gt p = 1.533 kg*m/s`

**Hence, evaluating the momentum when the ball strikes the ground yields `p = 1.533 kg*m/s` .**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now