Balance the chemical equation KClO3 + P4-> P4O10 + KCl

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justaguide eNotes educator| Certified Educator

The chemical equation `KClO_3 + P_4 -> P_4O_(10) + KCl` has to be balanced.

A balanced chemical equation has an equal number of atoms of each element on both the sides. It is also important to keep in mind that the molecules of any of the compounds that form the equation can only be present in whole numbers.

`KClO_3 + P_4 -> P_4O_(10) + KCl` 

Here, the compound `KClO_3` has 3 atoms of oxygen while `P_4O_(10)` has 10 atoms. This requires adding a coefficient of 10 to `KClO_3` and a coefficient of 3 to `P_4O_10`. To balance the phosphorus atoms, a coefficient of 3 has to be added to `P_4` and to balance the potassium and chlorine atoms a coefficient of 10 has to be used for KCl.

The balanced equation is: `10 KClO_3 + 3 P_4 -> 3 P_4O_(10) + 10 KCl`

ayl0124 | Student

When balancing a chemical equation, look at all the elements individually. In the reactants, we have:

  • 1 K
  • 1 Cl
  • 3 O
  • 4 P

And in the products we have:

  • 1 K
  • 1 Cl
  • 10 O
  • 4 P

Oxygen is the only element that does not match. Since matter cannot be created nor destroyed, we must balance the equation. Set the O equal on both sides of the equation. The lowest common multiple between the two is 30.

`10KClO_3 + P_4 -> 3P_4O_10 + KCl`

Now, K and P are unbalanced. Make sure both are balanced as well.

`10KClO_3 + 3P_4 -> 3P_4O_10 + 10KCl`

Finally, on both sides of the equation, there are equal parts of each element.

  • 10 K
  • 10 Cl
  • 30 O
  • 12 P
parama9000 | Student

10KCIO3+ 3P4--->3P4O10+10KCl

Yojana_Thapa | Student

(10)KClO3 + (3)P4-> (3)P4O10 + (10)KCl

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