Assuming perfect efficient transfer of energy,how long would it take 2.6Kg of 239PU to turn 4.2Kg of ice at -10 celsius into 4.2Kg of H20 vapour with a temperature of 128 celsius?How much mass is lost...
Assuming perfect efficient transfer of energy,how long would it take 2.6Kg of 239PU to turn 4.2Kg of ice at -10 celsius into 4.2Kg of H20 vapour
with a temperature of 128 celsius?How much mass is lost each time one of these atoms decay?
-primary isotopes involved in nuclear decay are 239Pu --> 235U
- print Print
- list Cite
Expert Answers
calendarEducator since 2013
write455 answers
starTop subjects are Science, Math, and History
First let us compute how much energy one needs to turn the ice into vapour.
`Q = m_(ice)*c_(ice)*10 +m_(ice)*lambda_(ice) +m_(water)*c_(water)*100 +m_(water)*lambda_(water) +m_(vapour)*c_(vapour)*28`
`Q =4.2*2110*10 +4.2*334*10^3+4.2*4180*100+4.2*2260*10^3+4.2*2080*28=`
`=1.298*10^7 J =13 MJ `
Second let us write the fission equation of (239)Pu
`(239)Pu = (235)U + (4)He`
The decay heat per mass unit for this reaction is known
`Q/(m*t) =P/m = 1.9 W/(kg)`
Therefore for a total mass `m =2.6 kg` of fissionable material we get
`Q/t = P= 2.6*1.9 =4.94 W`
Now the total time that is needed to transform ice into vapour comes from
`P*t = Q`
`t=Q/P =(13*10^6)/4.94 =2.63*10^6 seconds=731 hours =30.46 days`
Related Questions
- What is the significance of atomic nuclear decay?
- 1 Educator Answer
- What is the daughter isotope of carbon-14 decay?
- 1 Educator Answer
- How many grams of ice at -14 degrees Celsius are needed to cool 200 grams of water from 25...
- 1 Educator Answer
- Write the balanced nuclear equation representing the beta and gamma radiation emission of the...
- 1 Educator Answer
- help balancing nuclear equations the question is : write a nuclear equation for the alpha decay...
- 1 Educator Answer
Unlock This Answer Now
Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.