Assuming perfect efficient transfer of energy,how long would it take 2.6Kg of 239PU to turn 4.2Kg of ice at -10 celsius into 4.2Kg of H20 vapour with a temperature of 128 celsius?How much mass is lost...

Assuming perfect efficient transfer of energy,how long would it take 2.6Kg of 239PU to turn 4.2Kg of ice at -10 celsius into 4.2Kg of H20 vapour

with a temperature of 128 celsius?How much mass is lost each time one of these atoms decay? 

-primary isotopes involved in nuclear decay are 239Pu --> 235U

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First let us compute how much energy one needs to turn the ice into vapour.

`Q = m_(ice)*c_(ice)*10 +m_(ice)*lambda_(ice) +m_(water)*c_(water)*100 +m_(water)*lambda_(water) +m_(vapour)*c_(vapour)*28`

`Q =4.2*2110*10...

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