# area of trianglehow is possible to determine triangle area whose sides are x and y axis and the line x-2. i don't know the height and the base or something to help.

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Since you are given that the height and the base are the x and y-axis, all we need to do is find the intersection points between the axis and the line x-2.

==> The intersection point between the x-axis and the line x-2 are the point where the y= 0

==> x-2 = 0 ==> x= 2

==> The point of intersection is (2, 0).

Then, the length of the base is 2 units.

Now we will determine the intersection point between the y-axis and the the line x-2.

==> x= 0 ==> y= -2

Then the intersection point is ( 0, -2)

Then, the length of the height is 2.

Now we will calculate the area.

==> a = (1/2) * 2 * 2 = 2

**Then the area is a = 2 square units.**

We'll calculate the area of the right triangle as being the half of the product of the legs of triangle.

A = x*y/2

We'll determine x andy intercepting points of the line y = x - 2:

For y=0 => x - 2 = 0

x = 2

The x intercepting point is (2 ; 0).

For x = 0 => y = -2

The y intercepting point is (0 ; -2).

The area is:

A = 2*2/2

A = 2 square units